3^2x-4(3^1)+27=0

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Solution for 3^2x-4(3^1)+27=0 equation: 



3^2x-4(3^1)+27=0

We add all the numbers together, and all the variables

3^2x-16=0

We move all terms containing x to the left, all other terms to the right

3^2x=16

x=16/1

x=16

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